Day 3: Mull It Over

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FAQ

  • Hammerheart@programming.dev
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    22 days ago

    I did part 2 live with the python interactive shell. I deleted all the stuff where I was just exploring ideas.

    part 1:

    import re
    
    def multiply_and_add(data: "str") -> int:
        digit_matches = re.findall(r"mul\(\d{0,3},\d{0,3}\)", data)
        result = 0
        for _ in digit_matches:
            first = _.split("(")[1].split(")")[0].split(",")[0]
            second = _.split("(")[1].split(")")[0].split(",")[1]
            result += int(first) * int(second)
    
        return result
    
    with open("input") as file:
        data = file.read()
    
    
    answer = multiply_and_add(data)
    print(answer)
    

    part 2:

    Python 3.11.2 (main, Aug 26 2024, 07:20:54) [GCC 12.2.0] on linux
    Type "help", "copyright", "credits" or "license" for more information.
    >>> import solution2
    <re.Match object; span=(647, 651), match='do()'>
    >>> from solution2 import *
    >>> split_on_dont = data.split("don't()")
    >>> valid = []
    >>> valid.append(split_on_dont[0])
    >>> for substring in split_on_dont[1:]:
    ...     subsubstrings = substring.split("do()", maxsplit=1)
    ...     for subsubstring in subsubstrings[1:]:
    ...             valid.append(subsubstring)
    ...
    >>> answer = 0
    >>> for _ in valid:
    ...     answer += multiply_and_add(_)
    ...
    >>> answer
    103811193