0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 1 month agoNot my problem sortinfosec.pubimagemessage-square70fedilinkarrow-up1763arrow-down114
arrow-up1749arrow-down1imageNot my problem sortinfosec.pub0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 1 month agomessage-square70fedilink
minus-squarexmunk@sh.itjust.workslinkfedilinkarrow-up96·1 month agoGuaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
minus-squarefrezik@midwest.sociallinkfedilinkarrow-up48·1 month agoYou still have to check that it’s sorted, which is O(n). We’ll also assume that destroying the universe takes constant time.
minus-squareBatmanAoD@programming.devlinkfedilinkarrow-up43·1 month agoIn the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
minus-squaregroet@feddit.orglinkfedilinkEnglisharrow-up13·1 month agoIt actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
minus-squareBenjaben@lemmy.worldlinkfedilinkarrow-up9·1 month ago We’ll also assume that destroying the universe takes constant time. Well yeah just delete the pointer to it!
minus-squarevithigar@lemmy.calinkfedilinkarrow-up16·1 month agoExcept you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
minus-squaredb2@lemmy.worldlinkfedilinkarrow-up7·1 month agoThere’s a bug in it now, that’s why we’re still here.
Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
You still have to check that it’s sorted, which is O(n).
We’ll also assume that destroying the universe takes constant time.
In the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
It actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
Eh, trillion is a constant
amortized O(0)
Well yeah just delete the pointer to it!
universe.take()Except you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
There’s a bug in it now, that’s why we’re still here.
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